Base | Representation |
---|---|
bin | 1100000001110100010010… |
… | …0111101000010000000011 |
3 | 1201211022221202201021122122 |
4 | 3000131010213220100003 |
5 | 3213141012004343210 |
6 | 44043351111554455 |
7 | 2533333432203041 |
oct | 300350447502003 |
9 | 51738852637578 |
10 | 13225355543555 |
11 | 4239929469071 |
12 | 15971b498ba2b |
13 | 74c1b80882ac |
14 | 33a1797a1391 |
15 | 17e04db0eb55 |
hex | c07449e8403 |
13225355543555 has 16 divisors (see below), whose sum is σ = 15940034470080. Its totient is φ = 10533880990848.
The previous prime is 13225355543537. The next prime is 13225355543557. The reversal of 13225355543555 is 55534555352231.
It is a cyclic number.
It is not a de Polignac number, because 13225355543555 - 222 = 13225351349251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13225355543497 and 13225355543506.
It is not an unprimeable number, because it can be changed into a prime (13225355543557) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 97512569 + ... + 97648101.
It is an arithmetic number, because the mean of its divisors is an integer number (996252154380).
Almost surely, 213225355543555 is an apocalyptic number.
13225355543555 is a deficient number, since it is larger than the sum of its proper divisors (2714678926525).
13225355543555 is a wasteful number, since it uses less digits than its factorization.
13225355543555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 220990.
The product of its digits is 33750000, while the sum is 53.
The spelling of 13225355543555 in words is "thirteen trillion, two hundred twenty-five billion, three hundred fifty-five million, five hundred forty-three thousand, five hundred fifty-five".
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