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13225355543557 is a prime number
BaseRepresentation
bin1100000001110100010010…
…0111101000010000000101
31201211022221202201021122201
43000131010213220100011
53213141012004343212
644043351111554501
72533333432203043
oct300350447502005
951738852637581
1013225355543557
114239929469073
1215971b498ba31
1374c1b80882b1
1433a1797a1393
1517e04db0eb57
hexc07449e8405

13225355543557 has 2 divisors, whose sum is σ = 13225355543558. Its totient is φ = 13225355543556.

The previous prime is 13225355543537. The next prime is 13225355543567. The reversal of 13225355543557 is 75534555352231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13191322304196 + 34033239361 = 3631986^2 + 184481^2 .

It is a cyclic number.

It is not a de Polignac number, because 13225355543557 - 223 = 13225347154949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13225355543498 and 13225355543507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13225355543537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6612677771778 + 6612677771779.

It is an arithmetic number, because the mean of its divisors is an integer number (6612677771779).

Almost surely, 213225355543557 is an apocalyptic number.

It is an amenable number.

13225355543557 is a deficient number, since it is larger than the sum of its proper divisors (1).

13225355543557 is an equidigital number, since it uses as much as digits as its factorization.

13225355543557 is an evil number, because the sum of its binary digits is even.

The product of its digits is 47250000, while the sum is 55.

The spelling of 13225355543557 in words is "thirteen trillion, two hundred twenty-five billion, three hundred fifty-five million, five hundred forty-three thousand, five hundred fifty-seven".