| Base | Representation |
|---|---|
| bin | 11000011001111001… |
| … | …01010111101101100 |
| 3 | 1020211002222022201220 |
| 4 | 30030330222331230 |
| 5 | 203313121224400 |
| 6 | 10004040103340 |
| 7 | 642453202530 |
| oct | 141474527554 |
| 9 | 36732868656 |
| 10 | 13102133100 |
| 11 | 56138a3581 |
| 12 | 2657a64b50 |
| 13 | 130a5b13a4 |
| 14 | 8c4153bc0 |
| 15 | 51a3c87a0 |
| hex | 30cf2af6c |
13102133100 has 144 divisors (see below), whose sum is σ = 43550212608. Its totient is φ = 2979164160.
The previous prime is 13102133081. The next prime is 13102133101. The reversal of 13102133100 is 133120131.
It is a super-2 number, since 2×131021331002 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 13102133100.
It is not an unprimeable number, because it can be changed into a prime (13102133101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 389137 + ... + 421463.
It is an arithmetic number, because the mean of its divisors is an integer number (302432032).
Almost surely, 213102133100 is an apocalyptic number.
13102133100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13102133100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21775106304).
13102133100 is an abundant number, since it is smaller than the sum of its proper divisors (30448079508).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13102133100 is a wasteful number, since it uses less digits than its factorization.
13102133100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32544 (or 32537 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 13102133100 its reverse (133120131), we get a palindrome (13235253231).
The spelling of 13102133100 in words is "thirteen billion, one hundred two million, one hundred thirty-three thousand, one hundred".
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