Search a number
-
+
13010212212131 is a prime number
BaseRepresentation
bin1011110101010010110100…
…0100111100110110100011
31201001202122001120122201102
42331110231010330312203
53201124403311242011
643400450423425015
72511646121102531
oct275245504746643
951052561518642
1013010212212131
114166666688932
1215615718b516b
13734b1c6175a4
1432d9aa429151
1517865aeb273b
hexbd52d13cda3

13010212212131 has 2 divisors, whose sum is σ = 13010212212132. Its totient is φ = 13010212212130.

The previous prime is 13010212212113. The next prime is 13010212212163. The reversal of 13010212212131 is 13121221201031.

Together with previous prime (13010212212113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13010212212131 - 234 = 12993032342947 is a prime.

It is a super-2 number, since 2×130102122121312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13010212212181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505106106065 + 6505106106066.

It is an arithmetic number, because the mean of its divisors is an integer number (6505106106066).

Almost surely, 213010212212131 is an apocalyptic number.

13010212212131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13010212212131 is an equidigital number, since it uses as much as digits as its factorization.

13010212212131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 13010212212131 its reverse (13121221201031), we get a palindrome (26131433413162).

The spelling of 13010212212131 in words is "thirteen trillion, ten billion, two hundred twelve million, two hundred twelve thousand, one hundred thirty-one".