13010212212113 has 2 divisors, whose sum is σ = 13010212212114. Its totient is φ = 13010212212112.

The previous prime is 13010212212089. The next prime is 13010212212131. The reversal of 13010212212113 is 31121221201031.

Together with next prime (13010212212131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12963621853009 + 46590359104 = 3600503^2 + 215848^2 .

It is a cyclic number.

It is not a de Polignac number, because 13010212212113 - 2¹⁶ = 13010212146577 is a prime.

It is not a weakly prime, because it can be changed into another prime (13010212212163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505106106056 + 6505106106057.

It is an arithmetic number, because the mean of its divisors is an integer number (6505106106057).

Almost surely, 2^{13010212212113} is an apocalyptic number.

It is an amenable number.

13010212212113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13010212212113 is an equidigital number, since it uses as much as digits as its factorization.

13010212212113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 13010212212113 its reverse (31121221201031), we get a palindrome (44131433413144).

The spelling of 13010212212113 in words is "thirteen trillion, ten billion, two hundred twelve million, two hundred twelve thousand, one hundred thirteen".