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12404133035 = 571492378549
BaseRepresentation
bin10111000110101100…
…00000110010101011
31012000110120020122122
423203112000302223
5200400424224120
65410503341455
7616246251110
oct134326006253
935013506578
1012404133035
11529589a818
1224a215188b
131228ac23b8
1485957a907
154c8e9da25
hex2e3580cab

12404133035 has 16 divisors (see below), whose sum is σ = 17125560000. Its totient is φ = 8448602496.

The previous prime is 12404133031. The next prime is 12404133061. The reversal of 12404133035 is 53033140421.

It is a cyclic number.

It is not a de Polignac number, because 12404133035 - 22 = 12404133031 is a prime.

It is a super-2 number, since 2×124041330352 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12404132995 and 12404133013.

It is not an unprimeable number, because it can be changed into a prime (12404133031) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1184060 + ... + 1194489.

It is an arithmetic number, because the mean of its divisors is an integer number (1070347500).

Almost surely, 212404133035 is an apocalyptic number.

12404133035 is a deficient number, since it is larger than the sum of its proper divisors (4721426965).

12404133035 is a wasteful number, since it uses less digits than its factorization.

12404133035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2378710.

The product of its (nonzero) digits is 4320, while the sum is 26.

Adding to 12404133035 its reverse (53033140421), we get a palindrome (65437273456).

The spelling of 12404133035 in words is "twelve billion, four hundred four million, one hundred thirty-three thousand, thirty-five".

Divisors: 1 5 7 35 149 745 1043 5215 2378549 11892745 16649843 83249215 354403801 1772019005 2480826607 12404133035