Base | Representation |
---|---|
bin | 111001100001100110… |
… | …0111101110001010011 |
3 | 102210212022002110012021 |
4 | 1303003030331301103 |
5 | 4010444203241042 |
6 | 132430055112311 |
7 | 11632201005310 |
oct | 1630314756123 |
9 | 383768073167 |
10 | 123534040147 |
11 | 48432821861 |
12 | 1bb37372697 |
13 | b85941189b |
14 | 5d9c845d07 |
15 | 3330388867 |
hex | 1cc333dc53 |
123534040147 has 32 divisors (see below), whose sum is σ = 147546869760. Its totient is φ = 101200112640.
The previous prime is 123534040127. The next prime is 123534040159. The reversal of 123534040147 is 741040435321.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123534040147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (123534040127) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18865528 + ... + 18872074.
It is an arithmetic number, because the mean of its divisors is an integer number (4610839680).
Almost surely, 2123534040147 is an apocalyptic number.
123534040147 is a deficient number, since it is larger than the sum of its proper divisors (24012829613).
123534040147 is an equidigital number, since it uses as much as digits as its factorization.
123534040147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7651.
The product of its (nonzero) digits is 40320, while the sum is 34.
Adding to 123534040147 its reverse (741040435321), we get a palindrome (864574475468).
The spelling of 123534040147 in words is "one hundred twenty-three billion, five hundred thirty-four million, forty thousand, one hundred forty-seven".
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