12003103130232 has 64 divisors (see below), whose sum is σ = 30151370620800. Its totient is φ = 3981931228800.

The previous prime is 12003103130147. The next prime is 12003103130267. The reversal of 12003103130232 is 23203130130021.

It is a junction number, because it is equal to n+sod(n) for n = 12003103130199 and 12003103130208.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2834982 + ... + 5660682.

It is an arithmetic number, because the mean of its divisors is an integer number (471115165950).

Almost surely, 2^{12003103130232} is an apocalyptic number.

12003103130232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

12003103130232 is an abundant number, since it is smaller than the sum of its proper divisors (18148267490568).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12003103130232 is a wasteful number, since it uses less digits than its factorization.

12003103130232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2826556 (or 2826552 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 12003103130232 its reverse (23203130130021), we get a palindrome (35206233260253).

The spelling of 12003103130232 in words is "twelve trillion, three billion, one hundred three million, one hundred thirty thousand, two hundred thirty-two".