11332033120130 has 16 divisors (see below), whose sum is σ = 20588291951040. Its totient is φ = 4490450506992.

The previous prime is 11332033120099. The next prime is 11332033120157. The reversal of 11332033120130 is 3102133023311.

It is a super-2 number, since 2×11332033120130² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11332033120096 and 11332033120105.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5295341510 + ... + 5295343649.

It is an arithmetic number, because the mean of its divisors is an integer number (1286768246940).

Almost surely, 2^{11332033120130} is an apocalyptic number.

11332033120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11332033120130 is a deficient number, since it is larger than the sum of its proper divisors (9256258830910).

11332033120130 is a wasteful number, since it uses less digits than its factorization.

11332033120130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10590685273.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 11332033120130 its reverse (3102133023311), we get a palindrome (14434166143441).

The spelling of 11332033120130 in words is "eleven trillion, three hundred thirty-two billion, thirty-three million, one hundred twenty thousand, one hundred thirty".