Search a number
-
+
11311133113 = 71615876159
BaseRepresentation
bin10101000100011001…
…00011000110111001
31002012021220002122001
422202030203012321
5141131122224423
65110220501001
7550205021320
oct124214430671
932167802561
1011311133113
1148849267a5
1222380aa761
1310b3522997
147943410b7
1546304bcad
hex2a23231b9

11311133113 has 4 divisors (see below), whose sum is σ = 12927009280. Its totient is φ = 9695256948.

The previous prime is 11311133069. The next prime is 11311133159. The reversal of 11311133113 is 31133111311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11311133113 - 213 = 11311124921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11311133213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 807938073 + ... + 807938086.

It is an arithmetic number, because the mean of its divisors is an integer number (3231752320).

Almost surely, 211311133113 is an apocalyptic number.

It is an amenable number.

11311133113 is a deficient number, since it is larger than the sum of its proper divisors (1615876167).

11311133113 is an equidigital number, since it uses as much as digits as its factorization.

11311133113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1615876166.

The product of its digits is 81, while the sum is 19.

Adding to 11311133113 its reverse (31133111311), we get a palindrome (42444244424).

The spelling of 11311133113 in words is "eleven billion, three hundred eleven million, one hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 7 1615876159 11311133113