Search a number
-
+
112202220034 = 256101110017
BaseRepresentation
bin110100001111111000…
…1100000001000000010
3101201121120021100100001
41220133301200020002
53314242232020114
6123313414550214
711051322064012
oct1503761401002
9351546240301
10112202220034
1143648256673
12198b436836a
13a771827b98
14560587bc42
152dba602374
hex1a1fc60202

112202220034 has 4 divisors (see below), whose sum is σ = 168303330054. Its totient is φ = 56101110016.

The previous prime is 112202219999. The next prime is 112202220061. The reversal of 112202220034 is 430022202211.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 104492502009 + 7709718025 = 323253^2 + 87805^2 .

It is a super-2 number, since 2×1122022200342 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 112202219993 and 112202220020.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28050555007 + ... + 28050555010.

Almost surely, 2112202220034 is an apocalyptic number.

112202220034 is a deficient number, since it is larger than the sum of its proper divisors (56101110020).

112202220034 is an equidigital number, since it uses as much as digits as its factorization.

112202220034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56101110019.

The product of its (nonzero) digits is 384, while the sum is 19.

Adding to 112202220034 its reverse (430022202211), we get a palindrome (542224422245).

The spelling of 112202220034 in words is "one hundred twelve billion, two hundred two million, two hundred twenty thousand, thirty-four".

Divisors: 1 2 56101110017 112202220034