Base | Representation |
---|---|
bin | 10111011100111101011101… |
… | …000101001100001011000111 |
3 | 111112012120210102100211011012 |
4 | 113130331131011030023013 |
5 | 102004412333010130421 |
6 | 1003212130141032435 |
7 | 30503665145535611 |
oct | 2734753505141307 |
9 | 445176712324135 |
10 | 103145201255111 |
11 | 2a9576a8133a34 |
12 | b69a29325571b |
13 | 4572720ca0082 |
14 | 1b6837c025db1 |
15 | bdd09b69295b |
hex | 5dcf5d14c2c7 |
103145201255111 has 4 divisors (see below), whose sum is σ = 103157793767424. Its totient is φ = 103132608742800.
The previous prime is 103145201255101. The next prime is 103145201255137. The reversal of 103145201255111 is 111552102541301.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 103145201255111 - 234 = 103128021385927 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103145201255101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6296243870 + ... + 6296260251.
It is an arithmetic number, because the mean of its divisors is an integer number (25789448441856).
Almost surely, 2103145201255111 is an apocalyptic number.
103145201255111 is a deficient number, since it is larger than the sum of its proper divisors (12592512313).
103145201255111 is an equidigital number, since it uses as much as digits as its factorization.
103145201255111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12592512312.
The product of its (nonzero) digits is 6000, while the sum is 32.
Adding to 103145201255111 its reverse (111552102541301), we get a palindrome (214697303796412).
The spelling of 103145201255111 in words is "one hundred three trillion, one hundred forty-five billion, two hundred one million, two hundred fifty-five thousand, one hundred eleven".
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