Base | Representation |
---|---|
bin | 10111011100111101011101… |
… | …000101001100001010111101 |
3 | 111112012120210102100211010211 |
4 | 113130331131011030022331 |
5 | 102004412333010130401 |
6 | 1003212130141032421 |
7 | 30503665145535565 |
oct | 2734753505141275 |
9 | 445176712324124 |
10 | 103145201255101 |
11 | 2a9576a8133a25 |
12 | b69a293255711 |
13 | 4572720ca0075 |
14 | 1b6837c025da5 |
15 | bdd09b692951 |
hex | 5dcf5d14c2bd |
103145201255101 has 2 divisors, whose sum is σ = 103145201255102. Its totient is φ = 103145201255100.
The previous prime is 103145201255077. The next prime is 103145201255137. The reversal of 103145201255101 is 101552102541301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 100726012975225 + 2419188279876 = 10036235^2 + 1555374^2 .
It is a cyclic number.
It is not a de Polignac number, because 103145201255101 - 231 = 103143053771453 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103145201250101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51572600627550 + 51572600627551.
It is an arithmetic number, because the mean of its divisors is an integer number (51572600627551).
Almost surely, 2103145201255101 is an apocalyptic number.
It is an amenable number.
103145201255101 is a deficient number, since it is larger than the sum of its proper divisors (1).
103145201255101 is an equidigital number, since it uses as much as digits as its factorization.
103145201255101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 103145201255101 its reverse (101552102541301), we get a palindrome (204697303796402).
The spelling of 103145201255101 in words is "one hundred three trillion, one hundred forty-five billion, two hundred one million, two hundred fifty-five thousand, one hundred one".
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