101010121230307 has 8 divisors (see below), whose sum is σ = 102328450783200. Its totient is φ = 99695866885824.

The previous prime is 101010121230289. The next prime is 101010121230353. The reversal of 101010121230307 is 703032121010101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 101010121230307 - 2¹¹ = 101010121228259 is a prime.

It is a super-3 number, since 3×101010121230307³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an alternating number because its digits alternate between odd and even.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101010121230607) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1018752207 + ... + 1018851352.

It is an arithmetic number, because the mean of its divisors is an integer number (12791056347900).

Almost surely, 2^{101010121230307} is an apocalyptic number.

101010121230307 is a deficient number, since it is larger than the sum of its proper divisors (1318329552893).

101010121230307 is an equidigital number, since it uses as much as digits as its factorization.

101010121230307 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2037604205.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 101010121230307 its reverse (703032121010101), we get a palindrome (804042242240408).

The spelling of 101010121230307 in words is "one hundred one trillion, ten billion, one hundred twenty-one million, two hundred thirty thousand, three hundred seven".