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9280493113 is a prime number
BaseRepresentation
bin10001010010010100…
…10001011000111001
3212221202212220020011
420221022101120321
5123001301234423
64132521101521
7445656614143
oct105112213071
925852786204
109280493113
113a32661921
1219700278a1
13b4b90b258
1464078bc93
15394b35b0d
hex229291639

9280493113 has 2 divisors, whose sum is σ = 9280493114. Its totient is φ = 9280493112.

The previous prime is 9280493107. The next prime is 9280493119. The reversal of 9280493113 is 3113940829.

It is a balanced prime because it is at equal distance from previous prime (9280493107) and next prime (9280493119).

It can be written as a sum of positive squares in only one way, i.e., 9280046889 + 446224 = 96333^2 + 668^2 .

It is an emirp because it is prime and its reverse (3113940829) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9280493113 - 25 = 9280493081 is a prime.

It is a super-2 number, since 2×92804931132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (9280493119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4640246556 + 4640246557.

It is an arithmetic number, because the mean of its divisors is an integer number (4640246557).

Almost surely, 29280493113 is an apocalyptic number.

It is an amenable number.

9280493113 is a deficient number, since it is larger than the sum of its proper divisors (1).

9280493113 is an equidigital number, since it uses as much as digits as its factorization.

9280493113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 40.

The square root of 9280493113 is about 96335.3160216958. The cubic root of 9280493113 is about 2101.4723697815.

The spelling of 9280493113 in words is "nine billion, two hundred eighty million, four hundred ninety-three thousand, one hundred thirteen".