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5112067547 is a prime number
BaseRepresentation
bin1001100001011001…
…11111010111011011
3111012021020221100002
410300230333113123
540432142130142
62203133203215
7240452600006
oct46054772733
914167227302
105112067547
1121936a1014
12ba803050b
13636139052
14366d1453d
151edbe1a32
hex130b3f5db

5112067547 has 2 divisors, whose sum is σ = 5112067548. Its totient is φ = 5112067546.

The previous prime is 5112067507. The next prime is 5112067549. The reversal of 5112067547 is 7457602115.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5112067547 - 26 = 5112067483 is a prime.

It is a super-2 number, since 2×51120675472 = 52266469210181194418, which contains 22 as substring.

Together with 5112067549, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5112067547.

It is not a weakly prime, because it can be changed into another prime (5112067549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556033773 + 2556033774.

It is an arithmetic number, because the mean of its divisors is an integer number (2556033774).

Almost surely, 25112067547 is an apocalyptic number.

5112067547 is a deficient number, since it is larger than the sum of its proper divisors (1).

5112067547 is an equidigital number, since it uses as much as digits as its factorization.

5112067547 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 58800, while the sum is 38.

The square root of 5112067547 is about 71498.7240935109. The cubic root of 5112067547 is about 1722.6571902866.

The spelling of 5112067547 in words is "five billion, one hundred twelve million, sixty-seven thousand, five hundred forty-seven".