Base | Representation |
---|---|
bin | 11000101111001… |
… | …001100101100101 |
3 | 1001220220212010001 |
4 | 120233021211211 |
5 | 1322220410341 |
6 | 105103101301 |
7 | 13166361040 |
oct | 3057114545 |
9 | 1056825101 |
10 | 415013221 |
11 | 1a329a637 |
12 | b6ba1831 |
13 | 67c99c6c |
14 | 3d191c57 |
15 | 2667bd31 |
hex | 18bc9965 |
415013221 has 4 divisors (see below), whose sum is σ = 474300832. Its totient is φ = 355725612.
The previous prime is 415013191. The next prime is 415013227. The reversal of 415013221 is 122310514.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 122310514 = 2 ⋅61155257.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-415013221 is a prime.
It is a super-3 number, since 3×4150132213 (a number of 27 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (415013227) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29643795 + ... + 29643808.
It is an arithmetic number, because the mean of its divisors is an integer number (118575208).
Almost surely, 2415013221 is an apocalyptic number.
It is an amenable number.
415013221 is a deficient number, since it is larger than the sum of its proper divisors (59287611).
415013221 is an equidigital number, since it uses as much as digits as its factorization.
415013221 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 59287610.
The product of its (nonzero) digits is 240, while the sum is 19.
The square root of 415013221 is about 20371.8732815615. The cubic root of 415013221 is about 745.9115134620.
Adding to 415013221 its reverse (122310514), we get a palindrome (537323735).
It can be divided in two parts, 4150 and 13221, that added together give a palindrome (17371).
The spelling of 415013221 in words is "four hundred fifteen million, thirteen thousand, two hundred twenty-one".
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