Base | Representation |
---|---|
bin | 1100010100001011000101… |
… | …1110001101011101000011 |
3 | 1202221110221200001020120222 |
4 | 3011002301132031131003 |
5 | 3233322340341404101 |
6 | 44444303542453255 |
7 | 2565166345243241 |
oct | 305026136153503 |
9 | 52843850036528 |
10 | 13540714403651 |
11 | 4350648303276 |
12 | 1628345a3422b |
13 | 772b64b9bba6 |
14 | 34b53465d791 |
15 | 18735986c01b |
hex | c50b178d743 |
13540714403651 has 8 divisors (see below), whose sum is σ = 13555753246464. Its totient is φ = 13525680309120.
The previous prime is 13540714403647. The next prime is 13540714403683. The reversal of 13540714403651 is 15630441704531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13540714403651 - 22 = 13540714403647 is a prime.
It is a super-2 number, since 2×135407144036512 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13540714463651) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4534811 + ... + 6902603.
It is an arithmetic number, because the mean of its divisors is an integer number (1694469155808).
Almost surely, 213540714403651 is an apocalyptic number.
13540714403651 is a deficient number, since it is larger than the sum of its proper divisors (15038842813).
13540714403651 is a wasteful number, since it uses less digits than its factorization.
13540714403651 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2374141.
The product of its (nonzero) digits is 604800, while the sum is 44.
The spelling of 13540714403651 in words is "thirteen trillion, five hundred forty billion, seven hundred fourteen million, four hundred three thousand, six hundred fifty-one".
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