Base | Representation |
---|---|
bin | 10101010011101011… |
… | …00100100011001001 |
3 | 1002112020010001011211 |
4 | 22221311210203021 |
5 | 141411431434213 |
6 | 5131040253121 |
7 | 553322451562 |
oct | 125165444311 |
9 | 32466101154 |
10 | 11439327433 |
11 | 4940225016 |
12 | 22730111a1 |
13 | 1103c58601 |
14 | 7a7391169 |
15 | 46e42053d |
hex | 2a9d648c9 |
11439327433 has 2 divisors, whose sum is σ = 11439327434. Its totient is φ = 11439327432.
The previous prime is 11439327409. The next prime is 11439327457. The reversal of 11439327433 is 33472393411.
It is a balanced prime because it is at equal distance from previous prime (11439327409) and next prime (11439327457).
It can be written as a sum of positive squares in only one way, i.e., 7808903424 + 3630424009 = 88368^2 + 60253^2 .
It is an emirp because it is prime and its reverse (33472393411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11439327433 - 233 = 2849392841 is a prime.
It is not a weakly prime, because it can be changed into another prime (11431327433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5719663716 + 5719663717.
It is an arithmetic number, because the mean of its divisors is an integer number (5719663717).
Almost surely, 211439327433 is an apocalyptic number.
It is an amenable number.
11439327433 is a deficient number, since it is larger than the sum of its proper divisors (1).
11439327433 is an equidigital number, since it uses as much as digits as its factorization.
11439327433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 163296, while the sum is 40.
The spelling of 11439327433 in words is "eleven billion, four hundred thirty-nine million, three hundred twenty-seven thousand, four hundred thirty-three".
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