95003 has 2 divisors, whose sum is σ = 95004. Its totient is φ = 95002.

The previous prime is 94999. The next prime is 95009. The reversal of 95003 is 30059.

It is a weak prime.

It is an emirp because it is prime and its reverse (30059) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 95003 - 2² = 94999 is a prime.

It is a Chen prime.

It is a plaindrome in base 14.

It is not a weakly prime, because it can be changed into another prime (95009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47501 + 47502.

It is an arithmetic number, because the mean of its divisors is an integer number (47502).

2⁹⁵⁰⁰³ is an apocalyptic number.

95003 is a deficient number, since it is larger than the sum of its proper divisors (1).

95003 is an equidigital number, since it uses as much as digits as its factorization.

95003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135, while the sum is 17.

The square root of 95003 is about 308.2255667527. The cubic root of 95003 is about 45.6295066544.

The spelling of 95003 in words is "ninety-five thousand, three".