Base | Representation |
---|---|
bin | 100111110101101011… |
… | …0101100100010101001 |
3 | 22011211100000101021102 |
4 | 1033223112230202221 |
5 | 2400203030131433 |
6 | 103145201051145 |
7 | 6116040165104 |
oct | 1175326544251 |
9 | 264740011242 |
10 | 85552973993 |
11 | 33312472693 |
12 | 146b7626ab5 |
13 | 80b5705746 |
14 | 41d846173b |
15 | 235ac544e8 |
hex | 13eb5ac8a9 |
85552973993 has 2 divisors, whose sum is σ = 85552973994. Its totient is φ = 85552973992.
The previous prime is 85552973981. The next prime is 85552973999. The reversal of 85552973993 is 39937925558.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 81337328809 + 4215645184 = 285197^2 + 64928^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-85552973993 is a prime.
It is a super-2 number, since 2×855529739932 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (85552973999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42776486996 + 42776486997.
It is an arithmetic number, because the mean of its divisors is an integer number (42776486997).
Almost surely, 285552973993 is an apocalyptic number.
It is an amenable number.
85552973993 is a deficient number, since it is larger than the sum of its proper divisors (1).
85552973993 is an equidigital number, since it uses as much as digits as its factorization.
85552973993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 91854000, while the sum is 65.
The spelling of 85552973993 in words is "eighty-five billion, five hundred fifty-two million, nine hundred seventy-three thousand, nine hundred ninety-three".
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