Search a number
-
+
815575165253 is a prime number
BaseRepresentation
bin10111101111001000001…
…00010110100101000101
32212222010211120010001222
423313210010112211011
5101330244220242003
61422400422130125
7112631466344042
oct13674404264505
92788124503058
10815575165253
11294979a119a2
12112092580945
135bba6a073a4
142b68cb0a1c9
151633586ac38
hexbde4116945

815575165253 has 2 divisors, whose sum is σ = 815575165254. Its totient is φ = 815575165252.

The previous prime is 815575165199. The next prime is 815575165261. The reversal of 815575165253 is 352561575518.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 734351305249 + 81223860004 = 856943^2 + 284998^2 .

It is a cyclic number.

It is not a de Polignac number, because 815575165253 - 28 = 815575164997 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 815575165195 and 815575165204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (815575165283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 407787582626 + 407787582627.

It is an arithmetic number, because the mean of its divisors is an integer number (407787582627).

Almost surely, 2815575165253 is an apocalyptic number.

It is an amenable number.

815575165253 is a deficient number, since it is larger than the sum of its proper divisors (1).

815575165253 is an equidigital number, since it uses as much as digits as its factorization.

815575165253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6300000, while the sum is 53.

The spelling of 815575165253 in words is "eight hundred fifteen billion, five hundred seventy-five million, one hundred sixty-five thousand, two hundred fifty-three".