Base | Representation |
---|---|
bin | 100101010110110111… |
… | …0111011010011001101 |
3 | 21200001221221011002111 |
4 | 1022231232323103031 |
5 | 2303244341434323 |
6 | 100504322224021 |
7 | 5540013126664 |
oct | 1125556732315 |
9 | 250057834074 |
10 | 80224171213 |
11 | 310284a924a |
12 | 1366aab5011 |
13 | 7746702cc4 |
14 | 3c5084dddb |
15 | 2147eeec0d |
hex | 12adbbb4cd |
80224171213 has 2 divisors, whose sum is σ = 80224171214. Its totient is φ = 80224171212.
The previous prime is 80224171207. The next prime is 80224171301. The reversal of 80224171213 is 31217142208.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 80203939209 + 20232004 = 283203^2 + 4498^2 .
It is a cyclic number.
It is not a de Polignac number, because 80224171213 - 29 = 80224170701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (80224171513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40112085606 + 40112085607.
It is an arithmetic number, because the mean of its divisors is an integer number (40112085607).
Almost surely, 280224171213 is an apocalyptic number.
It is an amenable number.
80224171213 is a deficient number, since it is larger than the sum of its proper divisors (1).
80224171213 is an equidigital number, since it uses as much as digits as its factorization.
80224171213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5376, while the sum is 31.
The spelling of 80224171213 in words is "eighty billion, two hundred twenty-four million, one hundred seventy-one thousand, two hundred thirteen".
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