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73111400893 is a prime number
BaseRepresentation
bin100010000010111000…
…1110111000110111101
320222201020222222111201
41010011301313012331
52144213004312033
653330435015501
75165524440166
oct1040561670675
9228636888451
1073111400893
1129008530673
1212204a3a591
136b81c34a7b
143777d3a76d
151d7d85c47d
hex1105c771bd

73111400893 has 2 divisors, whose sum is σ = 73111400894. Its totient is φ = 73111400892.

The previous prime is 73111400851. The next prime is 73111400899. The reversal of 73111400893 is 39800411137.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44758902969 + 28352497924 = 211563^2 + 168382^2 .

It is an emirp because it is prime and its reverse (39800411137) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 73111400893 - 213 = 73111392701 is a prime.

It is a super-2 number, since 2×731114008932 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (73111400899) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36555700446 + 36555700447.

It is an arithmetic number, because the mean of its divisors is an integer number (36555700447).

Almost surely, 273111400893 is an apocalyptic number.

It is an amenable number.

73111400893 is a deficient number, since it is larger than the sum of its proper divisors (1).

73111400893 is an equidigital number, since it uses as much as digits as its factorization.

73111400893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 37.

The spelling of 73111400893 in words is "seventy-three billion, one hundred eleven million, four hundred thousand, eight hundred ninety-three".