Base | Representation |
---|---|
bin | 1001001000011101100101011… |
… | …0000101010101011111011011 |
3 | 10010021100011101122020020110112 |
4 | 2102013121112011111133123 |
5 | 1133212213441444021220 |
6 | 10154424541032434535 |
7 | 252233661011055254 |
oct | 22207312605253733 |
9 | 3107304348206415 |
10 | 642623041001435 |
11 | 1768399a055183a |
12 | 600a8798248a4b |
13 | 217761289ac6c0 |
14 | b49919a59db2b |
15 | 4e461779435c5 |
hex | 24876561557db |
642623041001435 has 32 divisors (see below), whose sum is σ = 892774951004160. Its totient is φ = 440010511486848.
The previous prime is 642623041001407. The next prime is 642623041001449. The reversal of 642623041001435 is 534100140326246.
It is not a de Polignac number, because 642623041001435 - 222 = 642623036807131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 642623041001392 and 642623041001401.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5535500927 + ... + 5535617016.
It is an arithmetic number, because the mean of its divisors is an integer number (27899217218880).
Almost surely, 2642623041001435 is an apocalyptic number.
642623041001435 is a gapful number since it is divisible by the number (65) formed by its first and last digit.
642623041001435 is a deficient number, since it is larger than the sum of its proper divisors (250151910002725).
642623041001435 is a wasteful number, since it uses less digits than its factorization.
642623041001435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11071118027.
The product of its (nonzero) digits is 414720, while the sum is 41.
The spelling of 642623041001435 in words is "six hundred forty-two trillion, six hundred twenty-three billion, forty-one million, one thousand, four hundred thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.261 sec. • engine limits •