Base | Representation |
---|---|
bin | 101110101001011000001… |
… | …1011111010000011100100 |
3 | 211200220001012002201001011 |
4 | 1131102300123322003210 |
5 | 1320014313113430312 |
6 | 21345110223112004 |
7 | 1231116554003563 |
oct | 135226033720344 |
9 | 24626035081034 |
10 | 6411051311332 |
11 | 2051a033695a8 |
12 | 876608142604 |
13 | 37673741c9c5 |
14 | 1824219bbbda |
15 | b1b75ba8da7 |
hex | 5d4b06fa0e4 |
6411051311332 has 24 divisors (see below), whose sum is σ = 11810242533600. Its totient is φ = 3036708049536.
The previous prime is 6411051311299. The next prime is 6411051311377. The reversal of 6411051311332 is 2331131501146.
It is a super-2 number, since 2×64110513113322 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 6411051311294 and 6411051311303.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 750723 + ... + 3658645.
It is an arithmetic number, because the mean of its divisors is an integer number (492093438900).
Almost surely, 26411051311332 is an apocalyptic number.
It is an amenable number.
6411051311332 is a deficient number, since it is larger than the sum of its proper divisors (5399191222268).
6411051311332 is a wasteful number, since it uses less digits than its factorization.
6411051311332 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2936955 (or 2936953 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 31.
Adding to 6411051311332 its reverse (2331131501146), we get a palindrome (8742182812478).
The spelling of 6411051311332 in words is "six trillion, four hundred eleven billion, fifty-one million, three hundred eleven thousand, three hundred thirty-two".
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