Base | Representation |
---|---|
bin | 111010101101101011… |
… | …001011100011101011 |
3 | 20000201121010111000101 |
4 | 322231223023203223 |
5 | 2013103042220133 |
6 | 44543421050231 |
7 | 4361162243614 |
oct | 725553134353 |
9 | 200647114011 |
10 | 63043320043 |
11 | 248113464a0 |
12 | 102750b6977 |
13 | 5c390cb492 |
14 | 30a0b34c0b |
15 | 198ea0237d |
hex | eadacb8eb |
63043320043 has 4 divisors (see below), whose sum is σ = 68774530968. Its totient is φ = 57312109120.
The previous prime is 63043320017. The next prime is 63043320061. The reversal of 63043320043 is 34002334036.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 63043320043 - 221 = 63041222891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 63043319993 and 63043320020.
It is not an unprimeable number, because it can be changed into a prime (63043320143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2865605446 + ... + 2865605467.
It is an arithmetic number, because the mean of its divisors is an integer number (17193632742).
Almost surely, 263043320043 is an apocalyptic number.
63043320043 is a deficient number, since it is larger than the sum of its proper divisors (5731210925).
63043320043 is a wasteful number, since it uses less digits than its factorization.
63043320043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5731210924.
The product of its (nonzero) digits is 15552, while the sum is 28.
Adding to 63043320043 its reverse (34002334036), we get a palindrome (97045654079).
The spelling of 63043320043 in words is "sixty-three billion, forty-three million, three hundred twenty thousand, forty-three".
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