Base | Representation |
---|---|
bin | 10000001000101011001… |
… | …01110011010110111011 |
3 | 1222000000222220010211111 |
4 | 20010111211303112323 |
5 | 33040414212344121 |
6 | 1102405510541151 |
7 | 55024604564446 |
oct | 10042545632673 |
9 | 1860028803744 |
10 | 554413012411 |
11 | 1a4141768045 |
12 | 8b5479677b7 |
13 | 4038625853b |
14 | 1cb95a9865d |
15 | e64cb322e1 |
hex | 81159735bb |
554413012411 has 4 divisors (see below), whose sum is σ = 554437080792. Its totient is φ = 554388944032.
The previous prime is 554413012357. The next prime is 554413012451. The reversal of 554413012411 is 114210314455.
554413012411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 554413012411 - 217 = 554412881339 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (554413012451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11999605 + ... + 12045718.
It is an arithmetic number, because the mean of its divisors is an integer number (138609270198).
Almost surely, 2554413012411 is an apocalyptic number.
554413012411 is a deficient number, since it is larger than the sum of its proper divisors (24068381).
554413012411 is a wasteful number, since it uses less digits than its factorization.
554413012411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24068380.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 554413012411 its reverse (114210314455), we get a palindrome (668623326866).
The spelling of 554413012411 in words is "five hundred fifty-four billion, four hundred thirteen million, twelve thousand, four hundred eleven".
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