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55433024971 is a prime number
BaseRepresentation
bin110011101000000100…
…001101010111001011
312022002020000102202221
4303220010031113023
51402011323244341
641244322034511
74001452636462
oct635004152713
9168066012687
1055433024971
1121566552135
12a8b04a8a37
1352c55339bc
14297c1119d9
151696834ed1
hexce810d5cb

55433024971 has 2 divisors, whose sum is σ = 55433024972. Its totient is φ = 55433024970.

The previous prime is 55433024929. The next prime is 55433025083. The reversal of 55433024971 is 17942033455.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 55433024971 - 29 = 55433024459 is a prime.

It is not a weakly prime, because it can be changed into another prime (55433024921) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27716512485 + 27716512486.

It is an arithmetic number, because the mean of its divisors is an integer number (27716512486).

Almost surely, 255433024971 is an apocalyptic number.

55433024971 is a deficient number, since it is larger than the sum of its proper divisors (1).

55433024971 is an equidigital number, since it uses as much as digits as its factorization.

55433024971 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 453600, while the sum is 43.

The spelling of 55433024971 in words is "fifty-five billion, four hundred thirty-three million, twenty-four thousand, nine hundred seventy-one".