Search a number
-
+
55110250053 = 326123361117
BaseRepresentation
bin110011010100110100…
…111010111001000101
312021020201122202211100
4303110310322321011
51400331211000203
641152311530313
73660453252645
oct632464727105
9167221582740
1055110250053
1121410332601
12a820389999
1352736c0721
14294b2d0525
151678327ea3
hexcd4d3ae45

55110250053 has 6 divisors (see below), whose sum is σ = 79603694534. Its totient is φ = 36740166696.

The previous prime is 55110250043. The next prime is 55110250121. The reversal of 55110250053 is 35005201155.

55110250053 is a `hidden beast` number, since 5 + 5 + 1 + 102 + 500 + 53 = 666.

It can be written as a sum of positive squares in only one way, i.e., 55017455364 + 92794689 = 234558^2 + 9633^2 .

It is not a de Polignac number, because 55110250053 - 222 = 55106055749 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 55110249999 and 55110250026.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55110250043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3061680550 + ... + 3061680567.

Almost surely, 255110250053 is an apocalyptic number.

It is an amenable number.

55110250053 is a deficient number, since it is larger than the sum of its proper divisors (24493444481).

55110250053 is a wasteful number, since it uses less digits than its factorization.

55110250053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6123361123 (or 6123361120 counting only the distinct ones).

The product of its (nonzero) digits is 3750, while the sum is 27.

The spelling of 55110250053 in words is "fifty-five billion, one hundred ten million, two hundred fifty thousand, fifty-three".

Divisors: 1 3 9 6123361117 18370083351 55110250053