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5444143854117 = 310311760149969
BaseRepresentation
bin100111100111001000001…
…0000101011001000100101
3201021110021202010122002220
41033032100100223020211
51203144101311312432
615325001040422553
71101216650142243
oct117162020531045
921243252118086
105444143854117
111809937305921
1273b140917a59
133064c4132c37
1414b6d85d5793
15969347e072c
hex4f39042b225

5444143854117 has 8 divisors (see below), whose sum is σ = 7265899076160. Its totient is φ = 3625908934080.

The previous prime is 5444143854089. The next prime is 5444143854143. The reversal of 5444143854117 is 7114583414445.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5444143854117 - 228 = 5443875418661 is a prime.

It is a super-3 number, since 3×54441438541173 (a number of 39 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5444143854117.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5444143854157) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 880071892 + ... + 880078077.

It is an arithmetic number, because the mean of its divisors is an integer number (908237384520).

Almost surely, 25444143854117 is an apocalyptic number.

It is an amenable number.

5444143854117 is a deficient number, since it is larger than the sum of its proper divisors (1821755222043).

5444143854117 is a wasteful number, since it uses less digits than its factorization.

5444143854117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1760151003.

The product of its digits is 4300800, while the sum is 51.

The spelling of 5444143854117 in words is "five trillion, four hundred forty-four billion, one hundred forty-three million, eight hundred fifty-four thousand, one hundred seventeen".

Divisors: 1 3 1031 3093 1760149969 5280449907 1814714618039 5444143854117