Base | Representation |
---|---|
bin | 100111011001110010011… |
… | …1101010000001001101001 |
3 | 201011201100111202212210111 |
4 | 1032303210331100021221 |
5 | 1202211421003231040 |
6 | 15303502452414321 |
7 | 1066154065646245 |
oct | 116634475201151 |
9 | 21151314685714 |
10 | 5415500055145 |
11 | 17a8778665794 |
12 | 7356880173a1 |
13 | 3038aaa2286b |
14 | 14a17c33b425 |
15 | 95d09ca8dea |
hex | 4ece4f50269 |
5415500055145 has 4 divisors (see below), whose sum is σ = 6498600066180. Its totient is φ = 4332400044112.
The previous prime is 5415500055113. The next prime is 5415500055187.
5415500055145 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2303983980544 + 3111516074601 = 1517888^2 + 1763949^2 .
It is a cyclic number.
It is not a de Polignac number, because 5415500055145 - 25 = 5415500055113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5415500055098 and 5415500055107.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 541550005510 + ... + 541550005519.
It is an arithmetic number, because the mean of its divisors is an integer number (1624650016545).
Almost surely, 25415500055145 is an apocalyptic number.
It is an amenable number.
5415500055145 is a deficient number, since it is larger than the sum of its proper divisors (1083100011035).
5415500055145 is a wasteful number, since it uses less digits than its factorization.
5415500055145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1083100011034.
The product of its (nonzero) digits is 250000, while the sum is 40.
The spelling of 5415500055145 in words is "five trillion, four hundred fifteen billion, five hundred million, fifty-five thousand, one hundred forty-five".
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