Base | Representation |
---|---|
bin | 11000101000000100011001… |
… | …11000010110101010110011 |
3 | 21002202000011101000110120001 |
4 | 30110002030320112222303 |
5 | 24044221440140013443 |
6 | 311101404315330431 |
7 | 14256306351520660 |
oct | 1424021470265263 |
9 | 232660141013501 |
10 | 54153311251123 |
11 | 16289321477887 |
12 | 60a7336450a17 |
13 | 242a834abc346 |
14 | d53069da2a67 |
15 | 63d9ba270d4d |
hex | 31408ce16ab3 |
54153311251123 has 16 divisors (see below), whose sum is σ = 62036234726400. Its totient is φ = 46307101478400.
The previous prime is 54153311251043. The next prime is 54153311251139. The reversal of 54153311251123 is 32115211335145.
It is not a de Polignac number, because 54153311251123 - 233 = 54144721316531 is a prime.
It is a super-2 number, since 2×541533112511232 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54153371251123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20740428 + ... + 23204998.
It is an arithmetic number, because the mean of its divisors is an integer number (3877264670400).
Almost surely, 254153311251123 is an apocalyptic number.
54153311251123 is a deficient number, since it is larger than the sum of its proper divisors (7882923475277).
54153311251123 is a wasteful number, since it uses less digits than its factorization.
54153311251123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2472018.
The product of its digits is 54000, while the sum is 37.
Adding to 54153311251123 its reverse (32115211335145), we get a palindrome (86268522586268).
The spelling of 54153311251123 in words is "fifty-four trillion, one hundred fifty-three billion, three hundred eleven million, two hundred fifty-one thousand, one hundred twenty-three".
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