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54125543500 = 22537172339551
BaseRepresentation
bin110010011010001000…
…100100000001001100
312011201002202111101021
4302122020210001030
51341322114343000
640510454123524
73624165346240
oct623210440114
9164632674337
1054125543500
1120a55504a36
12a5a66505a4
1351476a9622
142896604420
15161bb6811a
hexc9a22404c

54125543500 has 192 divisors, whose sum is σ = 149267349504. Its totient is φ = 16705920000.

The previous prime is 54125543491. The next prime is 54125543513. The reversal of 54125543500 is 534552145.

It is a Harshad number since it is a multiple of its sum of digits (34).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1348725 + ... + 1388275.

It is an arithmetic number, because the mean of its divisors is an integer number (777434112).

Almost surely, 254125543500 is an apocalyptic number.

54125543500 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 54125543500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (74633674752).

54125543500 is an abundant number, since it is smaller than the sum of its proper divisors (95141806004).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

54125543500 is a wasteful number, since it uses less digits than its factorization.

54125543500 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39617 (or 39605 counting only the distinct ones).

The product of its (nonzero) digits is 60000, while the sum is 34.

The spelling of 54125543500 in words is "fifty-four billion, one hundred twenty-five million, five hundred forty-three thousand, five hundred".