Base | Representation |
---|---|
bin | 11000100101101001110110… |
… | …11110100111010101010001 |
3 | 21002110002000001011122220112 |
4 | 30102310323132213111101 |
5 | 24041342024314424023 |
6 | 310555323302451105 |
7 | 14250311313465143 |
oct | 1422647336472521 |
9 | 232402001148815 |
10 | 54070341170513 |
11 | 16257114a86228 |
12 | 609323ba33a95 |
13 | 2422a7154a3a5 |
14 | d4d0389acc93 |
15 | 63b76116d478 |
hex | 312d3b7a7551 |
54070341170513 has 8 divisors (see below), whose sum is σ = 56919079638720. Its totient is φ = 51221895806160.
The previous prime is 54070341170507. The next prime is 54070341170701. The reversal of 54070341170513 is 31507114307045.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 54070341170513 - 28 = 54070341170257 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54070341179513) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 72897245 + ... + 73635242.
It is an arithmetic number, because the mean of its divisors is an integer number (7114884954840).
Almost surely, 254070341170513 is an apocalyptic number.
It is an amenable number.
54070341170513 is a deficient number, since it is larger than the sum of its proper divisors (2848738468207).
54070341170513 is a wasteful number, since it uses less digits than its factorization.
54070341170513 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 146551927.
The product of its (nonzero) digits is 176400, while the sum is 41.
Adding to 54070341170513 its reverse (31507114307045), we get a palindrome (85577455477558).
The spelling of 54070341170513 in words is "fifty-four trillion, seventy billion, three hundred forty-one million, one hundred seventy thousand, five hundred thirteen".
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