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53803141 = 7231312551
BaseRepresentation
bin1100110100111…
…1100010000101
310202020111000221
43031033202011
5102233200031
65201104341
71222214320
oct315174205
9122214027
1053803141
1128409107
12160280b1
13b1ba4a2
1472077b7
154acba11
hex334f885

53803141 has 16 divisors (see below), whose sum is σ = 64677888. Its totient is φ = 43758000.

The previous prime is 53803133. The next prime is 53803151. The reversal of 53803141 is 14130835.

53803141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 53803141 - 23 = 53803133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53803121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19816 + ... + 22366.

It is an arithmetic number, because the mean of its divisors is an integer number (4042368).

Almost surely, 253803141 is an apocalyptic number.

It is an amenable number.

53803141 is a deficient number, since it is larger than the sum of its proper divisors (10874747).

53803141 is a wasteful number, since it uses less digits than its factorization.

53803141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2712.

The product of its (nonzero) digits is 1440, while the sum is 25.

The square root of 53803141 is about 7335.0624400887. The cubic root of 53803141 is about 377.5164468077.

Adding to 53803141 its reverse (14130835), we get a palindrome (67933976).

The spelling of 53803141 in words is "fifty-three million, eight hundred three thousand, one hundred forty-one".

Divisors: 1 7 23 131 161 917 2551 3013 17857 21091 58673 334181 410711 2339267 7686163 53803141