Base | Representation |
---|---|
bin | 110010000000110110… |
… | …100100001010101111 |
3 | 12010121112122112011222 |
4 | 302000312210022233 |
5 | 1334440024120434 |
6 | 40400423133555 |
7 | 3610525220111 |
oct | 620066441257 |
9 | 163545575158 |
10 | 53701395119 |
11 | 20858045a89 |
12 | a4a85a42bb |
13 | 50aa861658 |
14 | 28561553b1 |
15 | 15e47d472e |
hex | c80da42af |
53701395119 has 4 divisors (see below), whose sum is σ = 53706491520. Its totient is φ = 53696298720.
The previous prime is 53701395103. The next prime is 53701395239. The reversal of 53701395119 is 91159310735.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53701395119 - 24 = 53701395103 is a prime.
It is a super-2 number, since 2×537013951192 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 53701395119.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53701395019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2532362 + ... + 2553479.
It is an arithmetic number, because the mean of its divisors is an integer number (13426622880).
Almost surely, 253701395119 is an apocalyptic number.
53701395119 is a deficient number, since it is larger than the sum of its proper divisors (5096401).
53701395119 is a wasteful number, since it uses less digits than its factorization.
53701395119 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5096400.
The product of its (nonzero) digits is 127575, while the sum is 44.
The spelling of 53701395119 in words is "fifty-three billion, seven hundred one million, three hundred ninety-five thousand, one hundred nineteen".
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