Base | Representation |
---|---|
bin | 100111000001000101010… |
… | …1000011110110011011011 |
3 | 200222122102000102112021111 |
4 | 1032002022220132303123 |
5 | 1200324241413200042 |
6 | 15223250115521151 |
7 | 1062265246611160 |
oct | 116021250366333 |
9 | 20878360375244 |
10 | 5362445053147 |
11 | 17882224854a6 |
12 | 72733bbb91b7 |
13 | 2cb8a4081560 |
14 | 147787da8067 |
15 | 94752108517 |
hex | 4e08aa1ecdb |
5362445053147 has 32 divisors (see below), whose sum is σ = 6666045120000. Its totient is φ = 4200521511168.
The previous prime is 5362445053139. The next prime is 5362445053169. The reversal of 5362445053147 is 7413505442635.
It is a cyclic number.
It is not a de Polignac number, because 5362445053147 - 23 = 5362445053139 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5362445053147.
It is not an unprimeable number, because it can be changed into a prime (5362445053547) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2972479 + ... + 4422727.
It is an arithmetic number, because the mean of its divisors is an integer number (208313910000).
Almost surely, 25362445053147 is an apocalyptic number.
5362445053147 is a deficient number, since it is larger than the sum of its proper divisors (1303600066853).
5362445053147 is a wasteful number, since it uses less digits than its factorization.
5362445053147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1450675.
The product of its (nonzero) digits is 6048000, while the sum is 49.
The spelling of 5362445053147 in words is "five trillion, three hundred sixty-two billion, four hundred forty-five million, fifty-three thousand, one hundred forty-seven".
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