Base | Representation |
---|---|
bin | 110001110011110011… |
… | …011110010101011111 |
3 | 12010001021201112110022 |
4 | 301303303132111133 |
5 | 1334013003342431 |
6 | 40323003102355 |
7 | 3602226405362 |
oct | 616363362537 |
9 | 163037645408 |
10 | 53482480991 |
11 | 20755514615 |
12 | a4472119bb |
13 | 50743b4274 |
14 | 283504c0d9 |
15 | 15d049107b |
hex | c73cde55f |
53482480991 has 2 divisors, whose sum is σ = 53482480992. Its totient is φ = 53482480990.
The previous prime is 53482480979. The next prime is 53482481099. The reversal of 53482480991 is 19908428435.
Together with next prime (53482481099) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53482480991 is a prime.
It is a super-3 number, since 3×534824809913 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53482480901) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26741240495 + 26741240496.
It is an arithmetic number, because the mean of its divisors is an integer number (26741240496).
Almost surely, 253482480991 is an apocalyptic number.
53482480991 is a deficient number, since it is larger than the sum of its proper divisors (1).
53482480991 is an equidigital number, since it uses as much as digits as its factorization.
53482480991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2488320, while the sum is 53.
The spelling of 53482480991 in words is "fifty-three billion, four hundred eighty-two million, four hundred eighty thousand, nine hundred ninety-one".
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