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53445120253 = 77635017179
BaseRepresentation
bin110001110001100100…
…111101000011111101
312002221200102102011021
4301301210331003331
51333423422322003
640315150224141
73601264012060
oct616144750375
9162850372137
1053445120253
1120736416978
12a4367b5051
135069732b15
1428300c48d7
1515cc0612bd
hexc7193d0fd

53445120253 has 4 divisors (see below), whose sum is σ = 61080137440. Its totient is φ = 45810103068.

The previous prime is 53445120221. The next prime is 53445120257. The reversal of 53445120253 is 35202154435.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53445120253 - 25 = 53445120221 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53445120257) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3817508583 + ... + 3817508596.

It is an arithmetic number, because the mean of its divisors is an integer number (15270034360).

Almost surely, 253445120253 is an apocalyptic number.

It is an amenable number.

53445120253 is a deficient number, since it is larger than the sum of its proper divisors (7635017187).

53445120253 is an equidigital number, since it uses as much as digits as its factorization.

53445120253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7635017186.

The product of its (nonzero) digits is 72000, while the sum is 34.

Adding to 53445120253 its reverse (35202154435), we get a palindrome (88647274688).

The spelling of 53445120253 in words is "fifty-three billion, four hundred forty-five million, one hundred twenty thousand, two hundred fifty-three".

Divisors: 1 7 7635017179 53445120253