53124400433 has 16 divisors (see below), whose sum is σ = 60067049280. Its totient is φ = 46640252736.

The previous prime is 53124400423. The next prime is 53124400451. The reversal of 53124400433 is 33400442135.

It is a cyclic number.

It is not a de Polignac number, because 53124400433 - 2¹⁰ = 53124399409 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (29).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53124400396 and 53124400405.

It is not an unprimeable number, because it can be changed into a prime (53124400423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1026335 + ... + 1076852.

It is an arithmetic number, because the mean of its divisors is an integer number (3754190580).

Almost surely, 2^53124400433 is an apocalyptic number.

It is an amenable number.

53124400433 is a deficient number, since it is larger than the sum of its proper divisors (6942648847).

53124400433 is a wasteful number, since it uses less digits than its factorization.

53124400433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2103296.

The product of its (nonzero) digits is 17280, while the sum is 29.

Adding to 53124400433 its reverse (33400442135), we get a palindrome (86524842568).

The spelling of 53124400433 in words is "fifty-three billion, one hundred twenty-four million, four hundred thousand, four hundred thirty-three".