Base | Representation |
---|---|
bin | 1111011101100000111… |
… | …00001000111101001101 |
3 | 1212210020002221021022011 |
4 | 13232300130020331031 |
5 | 32200440213103031 |
6 | 1044014313221221 |
7 | 53244436135261 |
oct | 7566034107515 |
9 | 1783202837264 |
10 | 531241144141 |
11 | 19533085a494 |
12 | 86b5b701811 |
13 | 3b1326b1896 |
14 | 1b9d842c0a1 |
15 | dc436c36b1 |
hex | 7bb0708f4d |
531241144141 has 2 divisors, whose sum is σ = 531241144142. Its totient is φ = 531241144140.
The previous prime is 531241144087. The next prime is 531241144163. The reversal of 531241144141 is 141441142135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 520641618025 + 10599526116 = 721555^2 + 102954^2 .
It is a cyclic number.
It is not a de Polignac number, because 531241144141 - 213 = 531241135949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531241144171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265620572070 + 265620572071.
It is an arithmetic number, because the mean of its divisors is an integer number (265620572071).
Almost surely, 2531241144141 is an apocalyptic number.
It is an amenable number.
531241144141 is a deficient number, since it is larger than the sum of its proper divisors (1).
531241144141 is an equidigital number, since it uses as much as digits as its factorization.
531241144141 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7680, while the sum is 31.
Adding to 531241144141 its reverse (141441142135), we get a palindrome (672682286276).
The spelling of 531241144141 in words is "five hundred thirty-one billion, two hundred forty-one million, one hundred forty-four thousand, one hundred forty-one".
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