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531241144141 is a prime number
BaseRepresentation
bin1111011101100000111…
…00001000111101001101
31212210020002221021022011
413232300130020331031
532200440213103031
61044014313221221
753244436135261
oct7566034107515
91783202837264
10531241144141
1119533085a494
1286b5b701811
133b1326b1896
141b9d842c0a1
15dc436c36b1
hex7bb0708f4d

531241144141 has 2 divisors, whose sum is σ = 531241144142. Its totient is φ = 531241144140.

The previous prime is 531241144087. The next prime is 531241144163. The reversal of 531241144141 is 141441142135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 520641618025 + 10599526116 = 721555^2 + 102954^2 .

It is a cyclic number.

It is not a de Polignac number, because 531241144141 - 213 = 531241135949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (531241144171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265620572070 + 265620572071.

It is an arithmetic number, because the mean of its divisors is an integer number (265620572071).

Almost surely, 2531241144141 is an apocalyptic number.

It is an amenable number.

531241144141 is a deficient number, since it is larger than the sum of its proper divisors (1).

531241144141 is an equidigital number, since it uses as much as digits as its factorization.

531241144141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7680, while the sum is 31.

Adding to 531241144141 its reverse (141441142135), we get a palindrome (672682286276).

The spelling of 531241144141 in words is "five hundred thirty-one billion, two hundred forty-one million, one hundred forty-four thousand, one hundred forty-one".