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5312140433 = 17401779249
BaseRepresentation
bin1001111001010000…
…01101010010010001
3111201012201200201222
410330220031102101
541334401443213
62235041334425
7245432306615
oct47450152221
914635650658
105312140433
112286623806
121043037415
1366871a582
14385715345
15211562808
hex13ca0d491

5312140433 has 8 divisors (see below), whose sum is σ = 5638653000. Its totient is φ = 4987187200.

The previous prime is 5312140391. The next prime is 5312140447. The reversal of 5312140433 is 3340412135.

It can be written as a sum of positive squares in 4 ways, for example, as 3439587904 + 1872552529 = 58648^2 + 43273^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5312140433 - 26 = 5312140369 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (5312140033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 382808 + ... + 396441.

It is an arithmetic number, because the mean of its divisors is an integer number (704831625).

Almost surely, 25312140433 is an apocalyptic number.

It is an amenable number.

5312140433 is a deficient number, since it is larger than the sum of its proper divisors (326512567).

5312140433 is a wasteful number, since it uses less digits than its factorization.

5312140433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 779667.

The product of its (nonzero) digits is 4320, while the sum is 26.

The square root of 5312140433 is about 72884.4320345573. The cubic root of 5312140433 is about 1744.8436444171.

Adding to 5312140433 its reverse (3340412135), we get a palindrome (8652552568).

The spelling of 5312140433 in words is "five billion, three hundred twelve million, one hundred forty thousand, four hundred thirty-three".

Divisors: 1 17 401 6817 779249 13247233 312478849 5312140433