Base | Representation |
---|---|
bin | 100110100110000100001… |
… | …0101101101100111000110 |
3 | 200210002122110120001202101 |
4 | 1031030020111231213012 |
5 | 1143401430134121014 |
6 | 15140452522302314 |
7 | 1055142404326225 |
oct | 115141025554706 |
9 | 20702573501671 |
10 | 5304424520134 |
11 | 17656593a0273 |
12 | 71804905799a |
13 | 2c628875c80c |
14 | 144a42386cbc |
15 | 92ea855e474 |
hex | 4d30856d9c6 |
5304424520134 has 8 divisors (see below), whose sum is σ = 7956842054400. Its totient is φ = 2652143835336.
The previous prime is 5304424520093. The next prime is 5304424520149. The reversal of 5304424520134 is 4310254244035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 5304424520093 and 5304424520102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34115409 + ... + 34270540.
It is an arithmetic number, because the mean of its divisors is an integer number (994605256800).
Almost surely, 25304424520134 is an apocalyptic number.
5304424520134 is a deficient number, since it is larger than the sum of its proper divisors (2652417534266).
5304424520134 is a wasteful number, since it uses less digits than its factorization.
5304424520134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68424734.
The product of its (nonzero) digits is 230400, while the sum is 37.
Adding to 5304424520134 its reverse (4310254244035), we get a palindrome (9614678764169).
The spelling of 5304424520134 in words is "five trillion, three hundred four billion, four hundred twenty-four million, five hundred twenty thousand, one hundred thirty-four".
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