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530354022331 = 775764860333
BaseRepresentation
bin1111011011110111001…
…00000010011110111011
31212200221021122210221211
413231323210002132323
532142131112203311
61043350303143551
753213444544310
oct7557344023673
91780837583854
10530354022331
11194a16023771
12869525a4bb7
133b020976b33
141b9526a4d07
15dbe088c821
hex7b7b9027bb

530354022331 has 4 divisors (see below), whose sum is σ = 606118882672. Its totient is φ = 454589161992.

The previous prime is 530354022329. The next prime is 530354022349. The reversal of 530354022331 is 133220453035.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 530354022331 - 21 = 530354022329 is a prime.

It is a super-2 number, since 2×5303540223312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 530354022293 and 530354022302.

It is not an unprimeable number, because it can be changed into a prime (530354022301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37882430160 + ... + 37882430173.

It is an arithmetic number, because the mean of its divisors is an integer number (151529720668).

Almost surely, 2530354022331 is an apocalyptic number.

530354022331 is a deficient number, since it is larger than the sum of its proper divisors (75764860341).

530354022331 is an equidigital number, since it uses as much as digits as its factorization.

530354022331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75764860340.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 530354022331 its reverse (133220453035), we get a palindrome (663574475366).

The spelling of 530354022331 in words is "five hundred thirty billion, three hundred fifty-four million, twenty-two thousand, three hundred thirty-one".

Divisors: 1 7 75764860333 530354022331