Base | Representation |
---|---|
bin | 11000000110101010011111… |
… | …00000011011010001001111 |
3 | 20221200021112012020212200221 |
4 | 30003111033200123101033 |
5 | 23421420303434102203 |
6 | 304422222511132211 |
7 | 14110344221102362 |
oct | 1403251740332117 |
9 | 227607465225627 |
10 | 53005525300303 |
11 | 159865761a9754 |
12 | 5b409ab214067 |
13 | 2376526b84634 |
14 | d136a42620d9 |
15 | 61dbde4beabd |
hex | 30354f81b44f |
53005525300303 has 16 divisors (see below), whose sum is σ = 54546343174656. Its totient is φ = 51482863353600.
The previous prime is 53005525300289. The next prime is 53005525300307. The reversal of 53005525300303 is 30300352550035.
It is a cyclic number.
It is not a de Polignac number, because 53005525300303 - 25 = 53005525300271 is a prime.
It is a super-2 number, since 2×530055253003032 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53005525300307) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15528 + ... + 10296178.
It is an arithmetic number, because the mean of its divisors is an integer number (3409146448416).
Almost surely, 253005525300303 is an apocalyptic number.
53005525300303 is a deficient number, since it is larger than the sum of its proper divisors (1540817874353).
53005525300303 is a wasteful number, since it uses less digits than its factorization.
53005525300303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10281534.
The product of its (nonzero) digits is 101250, while the sum is 34.
Adding to 53005525300303 its reverse (30300352550035), we get a palindrome (83305877850338).
The spelling of 53005525300303 in words is "fifty-three trillion, five billion, five hundred twenty-five million, three hundred thousand, three hundred three".
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