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52433431214041 is a prime number
BaseRepresentation
bin10111110110000000111000…
…00010101011011111011001
320212122120211222022010021101
423323000130002223133121
523333032131342322131
6303303330305311401
714021122206436423
oct1373003402533731
9225576758263241
1052433431214041
1115785990a90189
125a69b4a035561
1323345b37c2027
14cd3b12279813
1560dda94d0c61
hex2fb01c0ab7d9

52433431214041 has 2 divisors, whose sum is σ = 52433431214042. Its totient is φ = 52433431214040.

The previous prime is 52433431214029. The next prime is 52433431214069. The reversal of 52433431214041 is 14041213433425.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 51731696625625 + 701734588416 = 7192475^2 + 837696^2 .

It is a cyclic number.

It is not a de Polignac number, because 52433431214041 - 27 = 52433431213913 is a prime.

It is not a weakly prime, because it can be changed into another prime (52433431214441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26216715607020 + 26216715607021.

It is an arithmetic number, because the mean of its divisors is an integer number (26216715607021).

Almost surely, 252433431214041 is an apocalyptic number.

It is an amenable number.

52433431214041 is a deficient number, since it is larger than the sum of its proper divisors (1).

52433431214041 is an equidigital number, since it uses as much as digits as its factorization.

52433431214041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 138240, while the sum is 37.

Adding to 52433431214041 its reverse (14041213433425), we get a palindrome (66474644647466).

The spelling of 52433431214041 in words is "fifty-two trillion, four hundred thirty-three billion, four hundred thirty-one million, two hundred fourteen thousand, forty-one".