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52433431212053 is a prime number
BaseRepresentation
bin10111110110000000111000…
…00010101011000000010101
320212122120211222022000112202
423323000130002223000111
523333032131342241203
6303303330305254245
714021122206430553
oct1373003402530025
9225576758260482
1052433431212053
1115785990a89741
125a69b4a034385
1323345b37c1158
14cd3b12278bd3
1560dda94d0388
hex2fb01c0ab015

52433431212053 has 2 divisors, whose sum is σ = 52433431212054. Its totient is φ = 52433431212052.

The previous prime is 52433431211977. The next prime is 52433431212067. The reversal of 52433431212053 is 35021213433425.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41748423535204 + 10685007676849 = 6461302^2 + 3268793^2 .

It is a cyclic number.

It is not a de Polignac number, because 52433431212053 - 214 = 52433431195669 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 52433431211998 and 52433431212016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52433431212353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26216715606026 + 26216715606027.

It is an arithmetic number, because the mean of its divisors is an integer number (26216715606027).

Almost surely, 252433431212053 is an apocalyptic number.

It is an amenable number.

52433431212053 is a deficient number, since it is larger than the sum of its proper divisors (1).

52433431212053 is an equidigital number, since it uses as much as digits as its factorization.

52433431212053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 38.

Adding to 52433431212053 its reverse (35021213433425), we get a palindrome (87454644645478).

The spelling of 52433431212053 in words is "fifty-two trillion, four hundred thirty-three billion, four hundred thirty-one million, two hundred twelve thousand, fifty-three".