Base | Representation |
---|---|
bin | 100101110101100110101… |
… | …0010100101111010100111 |
3 | 200102011000122200221122111 |
4 | 1023223031102211322213 |
5 | 1140200311241200320 |
6 | 15021002051341451 |
7 | 1044466431012553 |
oct | 113531522457247 |
9 | 20364018627574 |
10 | 5200354631335 |
11 | 1725504686506 |
12 | 6bba442b1887 |
13 | 2b95119cb666 |
14 | 13d9ac9bc863 |
15 | 90416d96a5a |
hex | 4bacd4a5ea7 |
5200354631335 has 4 divisors (see below), whose sum is σ = 6240425557608. Its totient is φ = 4160283705064.
The previous prime is 5200354631323. The next prime is 5200354631341. The reversal of 5200354631335 is 5331364530025.
5200354631335 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5200354631335 - 211 = 5200354629287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 520035463129 + ... + 520035463138.
It is an arithmetic number, because the mean of its divisors is an integer number (1560106389402).
Almost surely, 25200354631335 is an apocalyptic number.
5200354631335 is a deficient number, since it is larger than the sum of its proper divisors (1040070926273).
5200354631335 is a wasteful number, since it uses less digits than its factorization.
5200354631335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1040070926272.
The product of its (nonzero) digits is 486000, while the sum is 40.
The spelling of 5200354631335 in words is "five trillion, two hundred billion, three hundred fifty-four million, six hundred thirty-one thousand, three hundred thirty-five".
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