513001 has 2 divisors, whose sum is σ = 513002. Its totient is φ = 513000.

The previous prime is 512999. The next prime is 513013. The reversal of 513001 is 100315.

513001 is nontrivially palindromic in base 14.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 301401 + 211600 = 549^2 + 460^2 .

It is a cyclic number.

It is not a de Polignac number, because 513001 - 2¹ = 512999 is a prime.

Together with 512999, it forms a pair of twin primes.

513001 is an undulating number in base 14.

It is not a weakly prime, because it can be changed into another prime (513031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256500 + 256501.

It is an arithmetic number, because the mean of its divisors is an integer number (256501).

2⁵¹³⁰⁰¹ is an apocalyptic number.

It is an amenable number.

513001 is a deficient number, since it is larger than the sum of its proper divisors (1).

513001 is an equidigital number, since it uses as much as digits as its factorization.

513001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15, while the sum is 10.

The square root of 513001 is about 716.2408812683. The cubic root of 513001 is about 80.0521014773.

Adding to 513001 its reverse (100315), we get a palindrome (613316).

Subtracting from 513001 its reverse (100315), we obtain a triangular number (412686 = T₉₀₈).

The spelling of 513001 in words is "five hundred thirteen thousand, one".